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Q10 P

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Physics For Scientists & Engineers
Found in: Page 439

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Short Answer

A swimming pool has dimensions 30.0 m×10.0 m and a flat bottom. When the pool is filled to a depth of 20.0 m with fresh water, what is the force exerted by the water on (a) the bottom? (b) On each end? (c) On each side?

(a) The force exerted by the water on the bottom is Fb=5.88×106Ndown .

(b) The force exerted by the water on each end is F=196kNoutward .

(c) The force exerted by the water on each side is F=588kNoutward .

See the step by step solution

Step by Step Solution

Step 1: Pressure:

The pressure in a fluid is the force per unit area exerted by the fluid on a surface:

P=FA

Where, P is the pressure, A is area, and F is the force exerted on the fluid.

Step 2: (a) The force exerted by the water on the bottom:

The pressure on the bottom due to the water is

Pb=ρgY=1.96×104 Pa

The force exerted by the water on the bottom is then

Fb=PbA=PbL×B=1.96×104Pa30.0 m×10.0 m=5.88×106N down

Hence, the force exerted by the water on the bottom is Fb=5.88×106Ndown .

Step 3: (b) The force exerted by the water on each end:

Pressure varies with depth. On a strip of height dy and length L, the force

F=PdA=PLdY=ρgYLdY

Which gives the integral as below.

F=0hρghLdY=12ρgLh2=12ρghLh=PaverageA

On each end,

F=PaverageA=9.8×103 Pa20.0m2=196kNoutward

Hence, the force exerted by the water on each end is role="math" localid="1663669149245" 196kNoutward .

Step 4: (c) The force exerted by the water on each side:

On the side,

F=PaverageA=9.8×103 Pa60.0m2=588kNoutward

Hence, the force exerted by the water on each side is F=588kNoutward .

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