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Fundamentals Of Physics
Found in: Page 124

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Short Answer

An amusement park ride consists of a car moving in a vertical circle on the end of a rigid boom of negligible mass. The combined weight of the car and riders is 5.0kN, and the circle’s radius is 10 m. At the top of the circle, what are the

(a) magnitude and

(b) direction (up or down) of the force on the car from the boom if the car’s speed is v = 5.0m/s?

What are (c)FB and

(d) the direction if v =12 m/s?

  1. The magnitude of the force on the car is 3.7×103 N.
  2. The direction of the force is upward.
  3. The magnitude of FB is 2.3×103 N.
  4. The direction of FB is downward.
See the step by step solution

Step by Step Solution

Step 1: Given data

  • The combined weight of the car and riders is 5.0 kN.
  • Circle’s radius is 10 m.

Step 2: To understand the concept

Here, the car is moving in a vertical circle on the end of a rigid boom of negligible mass instead of a normal downward force, and we are dealing with the force of the boom FB on the car, which is capable of pointing in any direction.

Assume it to be upward and apply Newton’s second law to the car (of a total weight of 5000 N. Note that the centripetal acceleration is downward (our choice for negative direction) for a body at the top of its circular trajectory.

Formula:

FBW=ma

Step 3: (a) To calculate the magnitude and direction of the force on the car from the boom if the car’s speed is v = 5.0 m/s 

Applying Newton’s law,

FBW=ma

Here, m=Wg

And a=v2r

If r=10 m and v=5.0 m/s,

FB=W1+agFB=W1+v2/rg

Substitute the values, and we get,

FB=50001+52/109.8FB=3.7×103 N

Thus, the magnitude of the force on the car is 3.7×103 N .

Step 4: (b) To calculate the magnitude and direction of the force on the car from the boom if the car’s speed is v = 5.0 m/s

FB=3.7×103 N

Thus, the positive sign indicates that FB is upwards

Step 5: (c), (d) To calculate the magnitude of the force on the car from the boom if the car’s speed is v = 12 m/s

If r=10 m and v=12.0 m/s,

FB=W1v2/rg

Substitute the values, and we get,

FB=50001122/109.8FB=2.3×103 N

Thus, the magnitude of FB is 2.3×103 N.

Step 6: (d) To calculate the direction of the force on the car from the boom if the car’s speed is v = 12 m/s

FB=2.3×103 N

Thus, the minus sign indicates that FB is downward.

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