Americas
Europe
Q52P
Expert-verifiedAn amusement park ride consists of a car moving in a vertical circle on the end of a rigid boom of negligible mass. The combined weight of the car and riders is , and the circle’s radius is . At the top of the circle, what are the
(a) magnitude and
(b) direction (up or down) of the force on the car from the boom if the car’s speed is ?
What are (c) and
(d) the direction if ?
Here, the car is moving in a vertical circle on the end of a rigid boom of negligible mass instead of a normal downward force, and we are dealing with the force of the boom on the car, which is capable of pointing in any direction.
Assume it to be upward and apply Newton’s second law to the car (of a total weight of 5000 N. Note that the centripetal acceleration is downward (our choice for negative direction) for a body at the top of its circular trajectory.
Formula:
Applying Newton’s law,
Here,
And
If and ,
Substitute the values, and we get,
Thus, the magnitude of the force on the car is .
Thus, the positive sign indicates that is upwards
If and ,
Substitute the values, and we get,
Thus, the magnitude of is .
Thus, the minus sign indicates that is downward.
94% of StudySmarter users get better grades.
Sign up for free