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Q. 8.19

Expert-verified
Found in: Page 345

### An Introduction to Thermal Physics

Book edition 1st
Author(s) Daniel V. Schroeder
Pages 356 pages
ISBN 9780201380279

# The critical temperature of iron is $1043K$. Use this value to make a rough estimate of the dipole-dipole interaction energy $\epsilon$, in electron-volts.

The dipole interaction energy of iron = $0.011eV$

See the step by step solution

## Step 1. Given information

Formula for critical temperature,

$k{T}_{c}=n\epsilon$

Here,

$k$ =Boltzmann constant,

$n$= number of nearest neighboring dipole

$\epsilon$= interaction energy.

## Step 2. To find the dipole interaction energy of iron

We have,

$\epsilon =\frac{k{T}_{c}}{n}$

Iron is BCC structure, and the value of $n$ is 8.0,

Substituting the value of $8.617×{10}^{-5}\mathrm{eV}/\mathrm{k}\text{=}k,1043\mathrm{k}\text{for critical temperature of iron}{T}_{c}\text{and}8.0\text{for}n$

$\epsilon =\frac{\left(8.617×{10}^{-5}\mathrm{eV}/\mathrm{k}\right)\left(1043\mathrm{k}\right)}{\left(8\right)}$

$=0.011\mathrm{eV}$

The dipole interaction energy of iron = $=0.011\mathrm{eV}$