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Expert-verified Found in: Page 200 ### An Introduction to Thermal Physics

Book edition 1st
Author(s) Daniel V. Schroeder
Pages 356 pages
ISBN 9780201380279 # Repeat the previous problem for the diagram in Figure 5.35 (right), which has an important qualitative difference. In this phase diagram, you should find that $\beta$ and liquid are in equilibrium only at temperatures below the point where the liquid is in equilibrium with infinitesimal amounts of $\alpha$ and $\beta$ . This point is called a peritectic point. Examples of systems with this behaviour include water + NaCl and leucite + quartz.

Starting at x=0 on the left, the$\alpha$ phase and the liquid phase are stable, then the liquid phase is stable, then the $\beta$ phase and the liquid phase are stable, then a narrow range of x where only the $\beta$ phase is stable, and ultimately just the liquid phase is stable.

See the step by step solution

## Step 1: Given information

$\beta$ and liquid are in equilibrium only at temperatures below the point where the liquid is in equilibrium with infinitesimal amounts of $\alpha$ and $\beta$ . This point is called a peritectic point.

## Step 2: Explanation

Consider the Gibbs free energy graph below, which shows a system with three solid phases: $\alpha ,\beta \text{and}\gamma$ One is a pure A substance, one is a pure B substance, and one is a mixture of the two. ## Step 3: Explanation

First, as shown in the diagram, we draw three tangent lines from left to right: first, the a phase plus the liquid phase are stable, then the liquid phase is stable, then the $\beta$ phase plus the liquid phase are stable, then a narrow range of x where only the $\beta$ phase is stable, and finally only the liquid phase is stable. ## Step 4: Calculations

The Gibbs free energy is given as:

$G=U-TS+PV$

At constant entropy and constant pressure, differentiate the Gibbs free energy to get:

$dG=dU-SdT+PdV$

By increasing the temperature

$\frac{\partial G}{\partial T}=-S$

We can see from this equation that as the temperature rises, the stability ranges of $\alpha$ and $\beta$ vanish. When we lower the temperature, the stability of $\gamma$ plus the liquid appears, as shown in the preceding figure for large x. As the temperature drops, the liquid's stable range narrows until it evaporates at two locations, one of which is known as the eutectic point (at which all the liquid freezes). Only at temperatures below the red point, where the liquid is in equilibrium with tiny amounts of $\alpha$ and $\beta$ and the liquid in equilibrium. This point is known as the peritectic point. ### Want to see more solutions like these? 