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Q.4.35

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An Introduction to Thermal Physics
Found in: Page 148
An Introduction to Thermal Physics

An Introduction to Thermal Physics

Book edition 1st
Author(s) Daniel V. Schroeder
Pages 356 pages
ISBN 9780201380279

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Short Answer

The magnetic field created by a dipole has a strength of approximately μ0/4πμ/r3, where r is the distance from the dipole and μ0 is the "permeability of free space," equal to exactly 4π×10-7 in SI units. (In the formula I'm neglecting the variation of field strength with angle, which is at most a factor of 2.) Consider a paramagnetic salt like iron ammonium alum, in which the magnetic moment μ of each dipole is approximately one Bohr magneton 9×10-24 J/T, with the dipoles separated by a distance of 1 nm. Assume that the dipoles interact only via ordinary magnetic forces.

(a) Estimate the strength of the magnetic field at the location of a dipole, due to its neighboring dipoles. This is the effective field strength even when there is no externally applied field.

(b) If a magnetic cooling experiment using this material begins with an external field strength of 1 T, by about what factor will the temperature decrease when the external field is turned off?

(c) Estimate the temperature at which the entropy of this material rises most steeply as a function of temperature, in the absence of an externally applied field.

(d) If the final temperature in a cooling experiment is significantly less than the temperature you found in part (c), the material ends up in a state where S/T is very small and therefore its heat capacity is very small. Explain why it would be impractical to try to reach such a low temperature with this material.

a) As a result, the strength of the magnetic field at a dipole's location is determined by the dipoles neighboring is 2.7×10-3 T.

b) As a result, the temperature drops by a factor of 370.

c) Thus, without an externally supplied field, the temperature at which this material's entropy grows most quickly as a function of temperature is1.0mK

d) As a result, attempting to achieve a very low temperature using this material would be impractical since heat leakage from the outside cannot be prevented, and a large heat capacity increases the amount of heat necessary to change the temperature.

See the step by step solution

Step by Step Solution

Part (a) - Step 1: To determine

The strength of the magnetic field at the location of a dipole, due to its neighboring dipoles.

Part (a) - Step 2: Explanation

GIVEN:

Magnetic field of a dipole has a strength μ04πμr3.A paramagnetic salt contains dipoles each having a magnetic moment of one Bohr magneton.

FORMULA:

Write the expression for a dipole's magnetic field.

B=μ0μ4πr3

Where r is the distance from dipole

μ is the magnetic moment and

μ0 is the magnetic permeability of free space.

Part (a) - Step 3: Calculation

CALCULATION:

To account for the differences in directions, multiply the number of neighbours by three.

Write the expression of the magnetic field at a dipole Bd due to three neighboring dipoles

Bd=3μ0μ4πr3 (1)

Substitute μ0 =4π×10-7 N/A2 μ = 9.0×10-24 J/T r =1.0×10-9 m in equation (1) Bd=34π×10-1 N/A29.0×10-24 J/T4π1.0×10-9 m3 =2.7×10-3 T

Hence he strength of the magnetic field at a dipole's location is determined by the dipoles neighboring is 2.7×10-3 T

Part (b) - Step 4: To find

When the external field is turned off, the temperature drops by this factor.

Part (b) - Step 5: Explanation

GIVEN:

Magnetic field of a dipole has a strength μ04πμr3.Each dipole in a paramagnetic salt has a magnetic moment of one Bohr magneton. In a magnetic cooling experiment, the external magnetic field of the starting value1 T is turned off.

FORMULA:

Write the expression of the magnetization M

M=NμtanhμBkT

Here, N is the number of dipoles, T is temperature andk is Boltzmann constant.

As a result, when the external field is turned off, the magnetization remains constant.

BiTi=BiTi

Here,

the subscript i denotes the initial values and

the subscript f denotes the final values.

Rearrange the above expression

TiTi=BiBt (2)

CALCULATION :

Substitute Bi=1 T and Bf=2.7×10-3 T for in expression (2)

TiTi=(IT)2.7×10-3 T = 370

Hence the temperature drops by a factor of 370

Part (c) - Step 6: To determine

The temperature at which this material's entropy rises most steeply as a function of temperature without the application of an external field.

Part (c) - Step 7: Explanation

GIVEN:

Magnetic field of a dipole has a strengthμ04πμr3 .A paramagnetic salt contains dipoles each having a magnetic moment of one Bohr magneton.

FORMULA:

Write the expression of the entropy-temperature formula

SNK=ln2cosh1x-1xtanh1x

Here, S is entropy,

K is a constant and

x stands for kTμB.

From the above expression, write the temperature expression Ts at which the entropy-temperature curve is the steepest.

Ts=μBxk (3)

CALCULATION:

Substitute μ=9.0×10-24 J/T, B=2.7×10-3 T, x=0.6 k=1.38×10-23 J/K in expression (3)

Ts=9.0×10-24 J/T2.7×10-3 T(0.6)1.38×10-23 J/K=1.0mK

Hence without an externally supplied field, the temperature at which this material's entropy grows most quickly as a function of temperature is 1.0mKTs=9.0×10-24 J/T2.7×10-3 T(0.6)1.38×10-23 J/K=1.0mK

Part (d) - Step 8: To find

Reasons why trying to obtain a very low temperature with this material would be impractical

Part (d) - Step 9: Explanation

The cooling operations are focused on the portion of the entropy-temperature curve that has the maximum slope at low magnetic fields.

Write the expression of the heat capacity cV at constant volume

c V=TST

Since the heat capacity at constant volume is proportional to the slope of the entropy-temperature curve, it is largest where the curve is steepest. For a high heat capacity, a great amount of heat is necessary to change the temperature noticeably.

It is not practical to reach a temperature lower than1.0mK because heat leaking from the outside cannot be entirely avoided.

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