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Q. 10.

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The Practice of Statistics for AP Examination
Found in: Page 564
The Practice of Statistics for AP Examination

The Practice of Statistics for AP Examination

Book edition 6th
Author(s) Daren Starnes, Josh Tabor
Pages 837 pages
ISBN 9781319113339

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Short Answer

Attitudes Refer to Exercise 4. In the study of older students’ attitudes, the sample mean SSHA score was 125.7 and the sample standard deviation was 29.8. A significance test yields a P-value of 0.0101.

a. Explain what it would mean for the null hypothesis to be true in this setting.

b. Interpret the P-value.

Part a) The correct mean score for the students who are at least 30 years of age is 115

Part b) The P-value is if the population mean is equal to115, then there is the possibility of1.01%of getting a random sample with a sample mean of125.7 or more.

See the step by step solution

Step by Step Solution

Part a) Step 1: Given information

From the previous exercise,

H0 : μ=115Ha : μ>115

μ is the population mean score of students who are at least 30 years of age.

Part a) Step 2: The objective is to explain the mean for the null hypothesis to be true in this setting

If the null hypothesis H0:μ=115 is correct, the true mean score for students who are at least 30years old is115

Part b) Step 1: Given information

n=45x¯=125.7s=29.8P=0.0101=1.01%

Part b) Step 2: The objective is to explain the p value

Result of the previous exercise:

H0 : μ=115Ha : μ>115

If the population means is115 then there is a 1.01% chance of getting a random sample with a sample means of125.7 or higher.

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