Log In Start studying!

Select your language

Suggested languages for you:
Answers without the blur. Sign up and see all textbooks for free! Illustration

Q. 14

Expert-verified
The Practice of Statistics for AP Examination
Found in: Page 790
The Practice of Statistics for AP Examination

The Practice of Statistics for AP Examination

Book edition 6th
Author(s) Daren Starnes, Josh Tabor
Pages 837 pages
ISBN 9781319113339

Answers without the blur.

Just sign up for free and you're in.

Illustration

Short Answer

The students in Mr. Shenk’s class measured the arm spans and heights (in inches) of a random sample of 18 students from their large high school. Here is computer output from a least-squares regression analysis of these data. Construct and interpret a 90% confidence interval for the slope of the population regression line. Assume that the conditions for performing inference are met.

Predictor Coef Stdev t-ratio P Constant 11.547 5.600 2.06 0.056 Armspan 0.84042 0.08091 10.39 0.000 S = 1.613 R-Sq = 87.1% R-Sq(adj) = 86.3%

We are 90% confident that the slope of the true regression line is between 0.69915114 and 0.98168886.

See the step by step solution

Step by Step Solution

Step 1: Given Information

We need to construct and interpret a 90 % confidence interval for the slope of the population regression line.

Step 2: Simplify

Consider:

n=18b=0.84042SEb=0.08091

The degrees of freedom in sample size decreased by 2:

df=n-2=18-2=16

The critical t-value can be found in table B in the row of df=16 and the column of c=90%

t'=1.746

The boundaries of the confidence interval then become:

b-t'×SEb=0.84042-1.746×0.08091=0.69915114role="math" localid="1654161040846" b+t'×SEb=0.84042+1.746×0.08091=0.98168886

Most popular questions for Math Textbooks

Exercises T12.4–T12.8 refer to the following setting. An old saying in golf is “You drive for show and you putt for dough.” The point is that good putting is more important than long driving for shooting low scores and hence winning money. To see if this is the case, data from a random sample of 69 of the nearly 1000 players on the PGA Tour’s world money list are examined. The average number of putts per hole (fewer is better) and the player’s total winnings for the previous season are recorded and a least-squares regression line was fitted to the data. Assume the conditions for
inference about the slope are met. Here is computer output from the regression analysis:

T12.6 The P -value for the test in Exercise T12.5 is 0.0087. Which of the following is a correct interpretation of this result?a. The probability there is no linear relationship between average number of putts per hole and total winnings for these 69 players is 0.0087.b. The probability there is no linear relationship between average number of putts per hole and total winnings for all players on the PGA Tour’s world money list is 0.0087.c. If there is no linear relationship between average number of putts per hole and total winnings for the players in the sample, the probability of getting a random sample of 69 players that yields a least-squares regression line with a slope of −4,139,198 or less is 0.0087.d. If there is no linear relationship between average number of putts per hole and total winnings for the players on the PGA Tour’s world money list, the probability of getting a random sample of 69 players that yields a least-squares regression line with a slope of −4,139,198 or less is 0.0087.e. The probability of making a Type I error is 0.0087.

Icon

Want to see more solutions like these?

Sign up for free to discover our expert answers
Get Started - It’s free

Recommended explanations on Math Textbooks

94% of StudySmarter users get better grades.

Sign up for free
94% of StudySmarter users get better grades.