Log In Start studying!

Select your language

Suggested languages for you:
Deutsch (DE)
Deutsch (UK)
Deutsch (US)

Americas

Europe

Answers without the blur. Sign up and see all textbooks for free! → Illustration

Q. 2

Expert-verified
The Practice of Statistics for AP
Found in: Page 733
The Practice of Statistics for AP

The Practice of Statistics for AP

Book edition 4th
Author(s) David Moore,Daren Starnes,Dan Yates
Pages 809 pages
ISBN 9781319113339

Answers without the blur.

Just sign up for free and you're in.

Register for Free I’ll do it later
Illustration

Short Answer

Which hypotheses would be appropriate for performing a chi-square test?

(a) The null hypothesis is that the closer students get to graduation, the less likely they are to be opposed to tuition increases. The alternative is that how close students are to graduation makes no difference in their opinion.

(b) The null hypothesis is that the mean number of students who are strongly opposed is the same for each of the four years. The alternative is that the mean is different for at least two of the four years.

(c) The null hypothesis is that the distribution of student opinion about the proposed tuition increase is the same for each of the four years at this university. The alternative is that the distribution is different for at least two of the four years.

(d) The null hypothesis is that year in school and student opinion about the tuition increase in the sample are independent. The alternative is that these variables are dependent.

(e) The null hypothesis is that there is an association between a year in school and opinion about the tuition increase at this university. The alternative hypothesis is that these variables are not associated.

(c) The null hypothesis is that the distribution of student opinion about the proposed tuition increase is the same for each of the four years at this university. The alternative is that the distribution is different for at least two of the four years.

See the step by step solution

Step by Step Solution

TABLE OF CONTENTS :
TABLE OF CONTENTS

Step 1: Given Information

Need to find Which hypotheses would be appropriate for performing a chi-square test.

Step 2: Explanation

We have been given a two-way table for 4 separate random samples, which implies that we will use a chi-square test for homogeneity (we use a chi-square test of association when the two-way table contains data about 1 sample).

The null hypothesis of a two-way table states that the distributions of each value of one of the variables are the same

H0 : The distribution of student opinion about the proposed tuition increase is the same for each of the 4 years at this university

The alternative hypothesis states the opposite of the null hypothesis.

Ha : The distribution is different for at least 2 of the 4 years

Most popular questions for Math Textbooks

A company claims that each batch of its deluxe mixed nuts contains 52% cashews, 27% almonds, 13% macadamia nuts, and 8% brazil nuts. To test this claim, a quality control inspector takes a random sample of 150 nuts from the latest batch. The one-way table below displays the sample data.

(a) State appropriate hypotheses for performing a test of the company’s claim.

(b) Calculate the expected counts for each type of nut. Show your work

An appropriate null hypothesis to test whether the trees in the forest are randomly distributed is

(a) H0:μ=25, where μ= the mean number of trees in each quadrant.

(b) H0:p=0.25, where p= the proportion of all trees in the forest that are in Quadrant 1 .

(c) H0:n1=n2=n3=n4=25, where ni is the number of trees from the sample in Quadrant i.

(d) H0:p1=p2=p3=p4=0.25, where pi is the actual proportion of trees in the forest that are in Quadrant i.

(e) H0:p^1=p^2=p^3=p^4=0.25, where p^i is the proportion of trees in the sample that are in Quadrant i.

How do U.S. residents who travel overseas for leisure differ from those who travel for business? The following is the breakdown by occupation:

Explain why we can’t use a chi-square test to learn whether these two distributions differ significantly.

Gregor Mendel (1822–1884), an Austrian monk, is considered the father of genetics. Mendel studied the inheritance of various traits in pea plants. One such trait is whether the pea is smooth or wrinkled. Mendel predicted a ratio of 3 smooth peas for every 1 wrinkled pea. In one experiment, he observed 423 smooth and 133 wrinkled peas. The data were produced in such a way that the Random and Independent conditions are met. Carry out a chi-square goodness-of-fit test based on Mendel’s prediction. What do you conclude?

In the United States, there is a strong relationship between education and smoking: well-educated people are less likely to smoke. Does a similar relationship hold in France? To find out, researchers recorded the level of education and smoking status of a random sample of 459 French men aged 20 to 60 years. 11 The two-way table below displays the data.

(a) Is the relationship between smoking status and educational level statistically significant? Give appropriate evidence to support your answer.

(b) Which cell in the table contributes most to the relationship in part (a)? Justify your answer.
Icon

Want to see more solutions like these?

Sign up for free to discover our expert answers
Get Started - It’s free

Recommended explanations on Math Textbooks

Decision Maths

Read explanation

Probability and Statistics

Read explanation

Statistics

Read explanation

Mechanics Maths

Read explanation

Geometry

Read explanation

Calculus

Read explanation

Pure Maths

Read explanation

94% of StudySmarter users get better grades.

Sign up for free
94% of StudySmarter users get better grades.