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Statistics For Business And Economics
Found in: Page 324
Statistics For Business And Economics

Statistics For Business And Economics

Book edition 13th
Author(s) James T. McClave, P. George Benson, Terry Sincich
Pages 888 pages
ISBN 9780134506593

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Short Answer

Length of job tenure. Researchers at the Terry College ofBusiness at the University of Georgia sampled 344 business students and asked them this question: “Over the course of your lifetime, what is the maximum number of years you expect to work for any one employer?” The sample resulted in x = 19.1 years. Assume that the sample of students was randomly selected from the 6,000 undergraduate students atthe Terry College and that = 6 years.

  1. Describe the sampling distribution of X¯.
  2. If the mean for the 6,000 undergraduate students is μ = 18.5 years, find Px¯>19.1.
  3. If the mean for the 6,000 undergraduate students is μ = 19.5 years, find Px¯>19.1.
  4. If, P(x¯>19.1)=0.5 what is μ ?
  5. If, Px¯>19.1=0.2 is μ greater than or less than 19.1years? Explain.

  1. The sampling distribution of X¯ is x¯μσ344
  2. If the mean for the 6,000 undergraduate students is μ= 18.5 years, PX¯>19.10.0318.
  3. If the mean for the 6,000 undergraduate students is μ= 19.5 years, find PX¯>19.10.8919.
  4. If PX¯>19.1=0.5,μ=19.1
  5. If PX¯>19.1=0.2,μ is less than 19.1.
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Step by Step Solution

Given information

In Terry College of Business at the University of Georgia, some researchers took a sample of 344 students from a population of 6000 undergraduate students randomly. Then they questioned the sampled students that what is the number of maximum years they expect to work for any one employer.

The survey resulted that x=19.1 years. The standard deviation σ=6years.

describe the sampling distribution of the sample mean

The sampling distribution of x¯ is described as,

Mean μx¯=μ

Standard deviation σx¯=σn=63440.323

z-score z=x¯μx¯σx¯=x¯μσ344

Calculate the probability Px¯>19.1 when  μ=18.5 years

We have the mean of the 6000 undergraduate students, that is μ=18.5.

Here, n=344. So, n is greater than 30. We can say that it is a relatively large sample size.

Therefore, by the Central Limit Theorem we can say that X¯~N18.5,0.323.

Thus,

PX¯>19.1=normalcdf19.1,999,18.5,0.3230.0318

Calculate the probability Px¯>19.1 when μ =19.5 years

We have the mean of the 6000 undergraduate students, that is μ=19.5.

Here, n=344. So, n is greater than 30. We can say that it is a relatively large sample size.

Therefore, by the Central Limit Theorem we can say that X¯~N19.5,0.323.

Thus,

PX¯>19.1=normalcdf19.1,999,19.5,0.3230.8919

Calculate the mean μ when Px¯>19.1=0.5

There is given that PX¯>19.1=0.5. So, we can conclude that 50% of the values of X¯ are below 19.1 and 50% are above 19.1.

Therefore, the distribution of X¯ is symmetric for this case. Thus, the expected value of X¯ must be 19.1.

Therefore, μX¯=19.1.

Referring to a. part, we know that μX¯=μ. So, the value of μ=19.1.

Determine the mean

We are considered that PX¯>19.1=0.2. So, we can conclude that 20% values of X¯ are above 19.1 and 80% of values are below 19.1.

Therefore, the distribution is not symmetric for this case. For this to possible, 19.1 will fall to the right of the mean of the distribution.

Therefore,

μX¯<19.1i.eμ<19.1

So,μ is less than 19.1 years.

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