Americas
Europe
5-47E
Expert-verifiedQuestion: Hotel guest satisfaction. Refer to the results of the 2015 North American Hotel Guest Satisfaction Index Study, Exercise 4.49 (p. 239). Recall that 15% of hotel guests were “delighted” with their experience (giving a rating of 10 out of 10); of these guests, 80% stated they would “definitely” recommend the hotel. In a random sample of 100 hotel guests, find the probability that fewer than 10 were delighted with their stay and would recommend the hotel.
The probability that fewer than 10 () delighted with their stay and would recommend the hotel is 0.2676.
Let p denotes the proportion of guests who were delighted with their stay and would recommend the hotel.
15% of guests were delighted with their experience, and of these, 80% would recommend the hotel
Therefore,
.
A random sample of size 100 is selected.
The probability that fewer than 10 () delighted with their stay and would recommend the hotel obtain as follows
In the z-table, the value at the intersection of -0.60 and 0.02 is the required probability.
Therefore, the required probability is 0.2676.
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