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Problem 2

Show that the square of the distance berween the two points $\left(x_{1}, y_{1}\right)\( and \)\left(x_{2}, y_{2}\right)$ on the circle \(x^{2}+y^{2}=a^{2}\) is equal to \(2\left(a^{2}-x_{1} x_{2}-y_{1} y_{2}\right)\)

Expert verified

The square of the distance between the two points on the circle is indeed equal to \(2\left(a^{2}-x_{1} x_{2}-y_{1} y_{2}\right)\), as we have proved by manipulation of the equation of a circle and the formula for calculating the square of the distance between two points in a 2D space.

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Chapter 1

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Chapter 1

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Chapter 1

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Chapter 1

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Chapter 1

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