Suggested languages for you:

Americas

Europe

Q79.

Expert-verifiedFound in: Page 480

Book edition
7th Edition

Author(s)
James Stewart, Lothar Redlin, Saleem Watson

Pages
948 pages

ISBN
9781337067508

**Orbit of the Earth Find the distance that the earth travels in ****one day in its path around the sun. Assume that a year has ****365 days and that the path of the earth around the sun is a ****circle of radius 93 million miles. [ Note: The path of the **

**small eccentricity, so it is nearly circular]**

The final distance that the earth travels in one day in its path around the sun is approximate **1.6 million miles**.

Radius of the sun $\left(r\right)=93$ million miles.

One full revolution ($2\pi $ rad) of the earth around the sun is a year, so in one day is equal to be central angle $\theta $ which is:

$\theta =\frac{2\pi}{365}$ radians

Now to find the distance that the earth travels in one day in its path around the sun, we can use below formula:

$s=r\theta $

Where:

$s=$distance that the earth travels in one day

$r=$radius of earth

$\theta =$central angle

The distance that the earth travels in one day in its path around the sun is:

$s=r\theta $

Put the given values in the formula:

$s=\frac{93\times 2\times \pi}{365}$

Put $\pi =3.14$, we get

role="math" localid="1648643379162" $s=\frac{93\times 2\times 3.14}{365}\phantom{\rule{0ex}{0ex}}s=\frac{584.04}{365}\phantom{\rule{0ex}{0ex}}=1.60092\phantom{\rule{0ex}{0ex}}=1.6\text{million miles}\phantom{\rule{0ex}{0ex}}$

94% of StudySmarter users get better grades.

Sign up for free