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Q2.

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Precalculus Mathematics for Calculus
Found in: Page 696
Precalculus Mathematics for Calculus

Precalculus Mathematics for Calculus

Book edition 7th Edition
Author(s) James Stewart, Lothar Redlin, Saleem Watson
Pages 948 pages
ISBN 9781337067508

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Short Answer

These exercises refer to the following system:

xy+z=2x+2y+z=33x+y2z=2

To eliminate x from the third equation, we add_______ times the first equation to the third equation. The third equation becomes _______=________

-3, 4y-5z & -4

See the step by step solution

Step by Step Solution

Step 1. Given information

From the given question, we have been given 3 equations

1. x-y+z=22. -x+2 y+z=-33. 3 x+y-2 z=2

Step 2. Concept used

An equation is a statement in that the values of two mathematical expressions are equal (indicated by the sign = ).

Step 3. Calculation

Lets we multiple the first equation by -3 and add it to the third equation, the coefficients of x cancel each other and x will be eliminated:

3(xy+z=2)3x+3y3z=6

Our first equation after multiplying by -3 is -3 x+3 y-3 z=-6

Adding the above equation and equation 3 (given in the question), we get

4 y-5 z=-4

So, the third equation becomes 4 y-5 z=-4.

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