Log In Start studying!

Select your language

Suggested languages for you:
Answers without the blur. Sign up and see all textbooks for free! Illustration

Q12.

Expert-verified
Precalculus Mathematics for Calculus
Found in: Page 688
Precalculus Mathematics for Calculus

Precalculus Mathematics for Calculus

Book edition 7th Edition
Author(s) James Stewart, Lothar Redlin, Saleem Watson
Pages 948 pages
ISBN 9781337067508

Answers without the blur.

Just sign up for free and you're in.

Illustration

Short Answer

Elimination Method

Use the elimination method to find all solutions of the system of equations.

2x5y=183x+4y=19

Hence, all solutions of the system of equations are x=1&y=4

See the step by step solution

Step by Step Solution

Step 1. Given information

We are given the system of linear equations that is-

2x5y=183x+4y=19

Step 2. Concept used

The system of linear equations is the collection of one or more linear equations involving the same set of variables.

We need to find all solutions to the system of equations.

By the Elimination Method, we will calculate the result.

Step 3. Calculation

We multiply the first equation by 2 and add the second equation to it to eliminate the x term.

3×[2x5y=18]6x15y=542×3x+4y=196x+8y=38

Further solving,

(6x6x)+(15y8y)=543823y=92y=4

We substitute the value of y in any of the original equations to get back the value of x

3x+4×4=193x+16=193x=3x=1

Recommended explanations on Math Textbooks

94% of StudySmarter users get better grades.

Sign up for free
94% of StudySmarter users get better grades.