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Q59.

Expert-verifiedFound in: Page 157

Book edition
7th Edition

Author(s)
James Stewart, Lothar Redlin, Saleem Watson

Pages
948 pages

ISBN
9781337067508

**Find the domain of the function $f\left(t\right)=\sqrt{t+1}$.**

The domain $\left({D}_{f}\right)$ of the function is $t\in [-1,\infty )$.

The given function is $f\left(t\right)=\sqrt{t+1}$. Now, by definition of domain of function, the domain of the function is defined for all real values of $\left(t\right)$ for which the function is defined.

From the square root function $f\left(t\right)=\sqrt{t+1}$, the domain is defined for all real numbers $\left(t\right)$ for which the expression inside the square root is greater than or equal to zero.

role="math" localid="1644580287740" $\begin{array}{c}t+1\ge 0\text{\hspace{0.17em}gives}\\ t\ge -1\end{array}$

Hence the domain of the function is $t\in [-1,\infty )$

The domain of the function is $t\in [-1,\infty )$.

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