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Q 85.

Precalculus Mathematics for Calculus
Found in: Page 544
Precalculus Mathematics for Calculus

Precalculus Mathematics for Calculus

Book edition 7th Edition
Author(s) James Stewart, Lothar Redlin, Saleem Watson
Pages 948 pages
ISBN 9781337067508

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Short Answer

Proving Identities

Verify the identity 1sinx1+sinx=(secxtanx)2

The expression 1sinx1+sinx=(secxtanx)2 is an identity.

See the step by step solution

Step by Step Solution

Step 1. Given information

An expression 1sinx1+sinx=(secxtanx)2

Step 2. Concept used

Split the expression into two halves, LHS and RHS, for such a query. Separate them and simplify them. It's an identity if both results are the same.

Step 3. Calculation

Now, simplify RHS of 1sinx1+sinx=(secxtanx)2

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