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Q. 1

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Precalculus Enhanced with Graphing Utilities

Found in: Page 193

Book edition 6th

Author(s) Sullivan

Pages 1200 pages

ISBN 9780321795465

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Short Answer

The intercepts of the equation $9 x^{2} + 4 y = 36$ are ____________.

The solution is $(- 2, 0), (2, 0), (0, 9)$ .

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Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1. Given information

Equation: $9 x^{2} + 4 y = 36$

Step 2. Calculation

Let $y = 0$

$9 x^{2} + 4 (0) = 36$

$\frac{9 x^{2}}{9} = \frac{36}{9}$

$\sqrt{x^{2}} = \sqrt{4}$

$x = \pm 2$

The x-intercepts are $- 2$ and $2$ . Now let $x = 0$

$9 (0) + 4 y = 36$

$\frac{4 y}{4} = \frac{36}{4}$

$y = 9$

The y-intercept is $9$ .

Therefore, the intercepts of the equation $9 x^{2} + 4 y = 36$ are $(- 2, 0), (2, 0), (0, 9)$ .

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