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Q 1.

Expert-verifiedFound in: Page 297

Book edition
6th

Author(s)
Sullivan

Pages
1200 pages

ISBN
9780321795465

Solve each inequality :

(a)$3x-7<8-2x$

(b)${x}^{2}-x-6>0$

The answer of part (a) is $x<3$

and part (b) is either $x>-2orx<-2$.

Given expression is $3x-7<8-2x$

Adding $\text{'}2x+7\text{'}$ both sides, we have,

$3x-7+2x+7<8-2x+2x+7\phantom{\rule{0ex}{0ex}}5x<15\phantom{\rule{0ex}{0ex}}x<3$

Given expression is ${x}^{2}-x-6>0$

${x}^{2}-x-6>0\phantom{\rule{0ex}{0ex}}(x-3)(x+2)>0$

Either $x>3andx>-2$this implies that $x>-2$

or $x<3andx<-2$ this implies that $x<-2$

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