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Q 1.

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Precalculus Enhanced with Graphing Utilities

Found in: Page 297

Book edition 6th

Author(s) Sullivan

Pages 1200 pages

ISBN 9780321795465

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Short Answer

Solve each inequality :
(a) $3 x - 7 < 8 - 2 x$
(b) $x^{2} - x - 6 > 0$

The answer of part (a) is $x < 3$

and part (b) is either $x > - 2 o r x < - 2$ .

See the step by step solution

Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Part (a) Step 1. Given information

Given expression is $3 x - 7 < 8 - 2 x$

Part (a) Step 2. Solution

Adding $' 2 x + 7'$ both sides, we have,

$3 x - 7 + 2 x + 7 < 8 - 2 x + 2 x + 7 5 x < 15 x < 3$

Part (b) Step 1. Given information

Given expression is $x^{2} - x - 6 > 0$

Part (b) Step 2. Solution

$x^{2} - x - 6 > 0 (x - 3) (x + 2) > 0$

Either $x > 3 a n d x > - 2$ this implies that $x > - 2$

or $x < 3 a n d x < - 2$ this implies that $x < - 2$

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