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Q. 43

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Precalculus Enhanced with Graphing Utilities

Found in: Page 865

Book edition 6th

Author(s) Sullivan

Pages 1200 pages

ISBN 9780321795465

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Short Answer

Two fair dice are rolled.
Determine the probability that the sum of the two dice is 3.

The probability is $\frac{1}{18}$

See the step by step solution

Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1. Given Information

The given statement is the sum of the two dice is 3.

Step 2. Calculation

The probability of an event is given by the number of ways the event can occur divided by the total number of outcomes in the sample space.

When two dice are rolled sample space is given by $n (S) = 36$ that is total number of elements in the sample space.

Let E represent the event 'the sum of two dice is 3' that is $n (E) = 2$

On substituting the values in the formula, we get,

$P = \frac{n (E)}{n (S)} = \frac{2}{36} = \frac{1}{18}$

Most popular questions for Math Textbooks

True or False In a probability model, the sum of all probabilities is 1.

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$C (18, 9)$

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