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Q40.

Expert-verified

Pre-algebra

Found in: Page 279

Book edition Common Core Edition

Author(s) Ron Larson, Laurie Boswell, Timothy D. Kanold, Lee Stiff

Pages 183 pages

ISBN 9780547587776

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Short Answer

Drinks A restaurant sells drinks in 3 sizes of cups: small, medium, and large. The small cup costs $.89 and holds 9 ounces. The medium cup costs $1.29 and holds 12 ounces. The large cup costs $1.59 and holds 15 ounces. Which size cup costs the least per ounce?

The small cup costs the least per ounce.

See the step by step solution

Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1 . Given

Given that

The small cup costs $0.89 and holds 9 ounces.

The medium cup costs $1.29 and holds 12 ounces.

The large cup costs $1.59 and holds 15 ounces.

Step 2 . To determine

We have to determine which size cup costs least per ounce.

Step 3 . Calculation

In order to find the size of cup that costs least per ounce, we will calculate the cost of each cup per ounce. For that, we find the unit rates.

Unit rate for the small cup is:

$\begin{array}{l} \frac{$ 0.89 \div 9}{9 ounces \div 9} [Divide numerator and denominator by 9] \\ \Rightarrow \frac{$ 0.099}{1 ounce} \end{array}$

So, the cost is $0.099 per ounce for the small cup.

Unit rate for the medium cup is:

$\begin{array}{l} \frac{$ 1.29 \div 12}{12 ounces \div 12} [Divide numerator and denominator by 12] \\ \Rightarrow \frac{$ 0.108}{1 ounce} \end{array}$

So, the cost is $0.108 per ounce for the medium cup.

Unit rate for the large cup is:

$\begin{array}{l} \frac{$ 1.59 \div 15}{15 ounces \div 15} [Divide numerator and denominator by 15] \\ \Rightarrow \frac{$ 0.106}{1 ounce} \end{array}$

So, the cost is $0.106 per ounce for the large cup.

Step 4 . Conclusion

Comparing the three prices we see that, $0.099 per ounce is the least cost. And it corresponds to the small cup.

It means the small cup costs the least.

Most popular questions for Math Textbooks

What is a unit rate? Give an example.

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$\frac{x}{8} = \frac{35}{56}$

Write the fraction in simplest form.

$\frac{14 x^{2} y^{3}}{35 x y^{2}}$

Solve the equation.

$\frac{1}{4} x - \frac{3}{8} = 9$

Use equivalent ratios to solve the proportion.

$\frac{11}{9} = \frac{y}{81}$

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