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Q12.

Expert-verifiedFound in: Page 274

Book edition
Common Core Edition

Author(s)
Ron Larson, Laurie Boswell, Timothy D. Kanold, Lee Stiff

Pages
183 pages

ISBN
9780547587776

**Solve the equation.**

**$\frac{1}{4}x-\frac{3}{8}=9$**

The solution of$\frac{1}{4}x-\frac{3}{8}=9$ is$x=\frac{75}{4}$ .

The given equation is$\frac{1}{4}x-\frac{3}{8}=9$ .

We have to solve the equation$\frac{1}{4}x-\frac{3}{8}=9$.

To solve the equation, we try to get x alone on a side:

$\begin{array}{c}\frac{1}{4}x-\frac{3}{8}=9\\ \frac{1}{4}x=9+\frac{3}{8}\text{}\left[\text{group like terms}\right]\text{}\\ \frac{1}{4}x=\frac{72+3}{8}\text{}\left[\text{write sum of numerator over denominator}\right]\\ \frac{1}{4}x=\frac{75}{8}\text{}\left[\text{add}\right]\\ x=\frac{75}{4}\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em} \hspace{0.17em}\hspace{0.17em} \hspace{0.17em}\hspace{0.17em}}\left[\text{multiply both side with 4}\right]\text{}\\ \text{}\\ \text{}\end{array}$

So, the solution of the equation $\frac{1}{4}x-\frac{3}{8}=9$ is$x=\frac{75}{4}$ .

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