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Q7.

Expert-verifiedFound in: Page 127

Book edition
Common Core Edition

Author(s)
Ron Larson, Laurie Boswell, Timothy D. Kanold, Lee Stiff

Pages
183 pages

ISBN
9780547587776

**Solve the equation. Check your solution.$\mathbf{16}\mathbf{=}\mathbf{8}(\mathbf{x}\mathbf{-}\mathbf{1})$**

The solution for the equation $16=8(x-1)$ is$x=3$ .

Write the original equation and separate the variable and constants.

$\begin{array}{c}16=8(x-1)\\ 16=8x-8\\ 16+8=8x-8+8\\ 24=8x\\ 8x=24\end{array}$

Now, divide both sides of the equation by 3.

$\begin{array}{c}\frac{8x}{8}=\frac{24}{8}\\ x=3\end{array}$

Therefore, the solution of the equation is$x=3$ .

To check the solution, write the original equation and substitute the value of *x*.

$16=8\left(x-1\right)$

Now, substitute$x=3$ and check the result.

$\begin{array}{c}16=8(3-1)\\ 16=8\left(2\right)\\ 16=16\end{array}$

As the left-hand side is equal to right hand side, this signifies that the solution is correct.

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