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Q4.

Expert-verified
Found in: Page 120

### Pre-algebra

Book edition Common Core Edition
Author(s) Ron Larson, Laurie Boswell, Timothy D. Kanold, Lee Stiff
Pages 183 pages
ISBN 9780547587776

# Check your solution. $2=6\mathrm{h}+20$

The solution for the equation $2=6h+20$ is$h=-3$.

See the step by step solution

## Step 1 – Separate the variables and constants

Write the original equation and separate the variables.

$\begin{array}{l}2=6h+20\\ 2-20=6h\\ -18=6h\end{array}$

## Step 2 – Solve for n

Divide both sides of the equation $-18=6h$ by 6.

$\begin{array}{l}\frac{-18}{6}=\frac{6h}{6}\\ h=-3\end{array}$

Therefore, the solution of the equation is $h=-3$.

## Step 3 – Check the solution

To check the solution, write the original equation and substitute the value of $h$.

$2=6h+20$

Now, substitute $h=-3$and check the result.

$\begin{array}{l}2=6\left(-3\right)+20\\ 2-20=6\left(-3\right)\\ -18=6\left(-3\right)\\ -18=-18\end{array}$

As the left-hand side is equal to right hand side, this signifies that the solution is correct.

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