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Expert-verified Found in: Page 133 ### Pre-algebra

Book edition Common Core Edition
Author(s) Ron Larson, Laurie Boswell, Timothy D. Kanold, Lee Stiff
Pages 183 pages
ISBN 9780547587776 # Find the perimeter of the square. The required perimeter of the square is 288

See the step by step solution

## Step-1 – Given

Given two sides of the square are $9x$ and $5x+32$.

## Step-2 – To determine

We have to find the perimeter of the square.

## Step-3 – Calculation

We know that each sides of a square are equal.

So, $9x=5x+32$

Then we solve the equation:

$\begin{array}{l}9x=5x+32\text{write the equation}\\ 9x-5x=32+5x-5x\text{subtract 5x from both sides}\\ 4x=32\text{simplify}\\ \frac{4x}{4}=\frac{32}{4}\text{divide each side by 4}\\ x=8\text{simplify}\end{array}$

Substituting the value of x in the expression of a side = $9x$ we get:

$\begin{array}{l}9x\\ =9×8\text{Substitute the value of}x\text{}\\ \text{=72 Multiply}\end{array}$

So the length of each side = 72

Hence,

$\begin{array}{l}\text{Perimeter}\left(P\right)=4×\text{each side of the sqaure}\\ \text{Perimeter}\left(P\right)=\text{4}×72\text{Substitute the value in the formula}\\ \text{Perimeter}\left(P\right)=288\text{units Multiply}\end{array}$

Therefore, $\text{Perimeter}\left(P\right)=288$ ### Want to see more solutions like these? 