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Q3.

Expert-verified
Found in: Page 126

### Pre-algebra

Book edition Common Core Edition
Author(s) Ron Larson, Laurie Boswell, Timothy D. Kanold, Lee Stiff
Pages 183 pages
ISBN 9780547587776

# Solve the equation. Check your solution.$\mathbf{13}\mathbf{=}\mathbf{2}\mathbf{y}\mathbf{-}\mathbf{3}\left(\mathbf{y}\mathbf{+}\mathbf{4}\right)$

The solution for the equation $13=2y-3\left(y+4\right)$ is localid="1650416876257" $y=-25$.

See the step by step solution

## Step 1 – Separate the variable and constants

Write the original equation and separate the variable and constants.

$\begin{array}{c}13+12=2y-3y-12+12\\ 25=2y-3y\\ -y=25\end{array}$

## Step 2 – Solve for y

Now, multiply both sides of the equation by -1.

$\begin{array}{c}-y\left(-1\right)=25\left(-1\right)\\ y=-25\end{array}$

Therefore, the solution of the equation is $y=-25$ .

## Step 3 – Check the solution

To check the solution, write the original equation and substitute the value of y.

$13=2y-3\left(y+4\right)$

Now, substitute $y=25$ and check the result.

$\begin{array}{c}13=2\left(-25\right)-3\left(\left(-25\right)+4\right)\\ 13=-50-3\left(-21\right)\\ 13=-50+63\\ 13=13\end{array}$

As the left-hand side is equal to right hand side, this signifies that the solution is correct.