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Q22.

Expert-verifiedFound in: Page 133

Book edition
Common Core Edition

Author(s)
Ron Larson, Laurie Boswell, Timothy D. Kanold, Lee Stiff

Pages
183 pages

ISBN
9780547587776

**Solve the equation. Check your solution.**

The solution for the equation $2\left(-4h-13\right)=37+13h$ is $h=-3$.

Write the original equation and separate the variable and constants.

$\begin{array}{c}2\left(-4h-13\right)=37+13h\\ -8h-26=37+13h\\ -8h-13h-26=37+13h-13h\text{}\left(\text{Subtract}13h\text{from both sides}\right)\\ -21h-26=37\\ -21h-26-37=37-37\text{}\left(\text{Subtract 37 from both sides}\right)\\ -21h-63=0\\ -21h=63\end{array}$

Now, divide both sides of the equation by -21.

$\begin{array}{c}\frac{-21h}{-21}=\frac{63}{-21}\\ h=-3\end{array}$Therefore, the solution of the equation is $h=-3$.

To check the solution, write the original equation and substitute the value of *h*.

$2\left(-4h-13\right)=37+13h$

Now, substitute $h=-3$ and check the result.

$\begin{array}{c}2\left(-4\left(-3\right)-13\right)=37+13\left(-3\right)\\ 2\left(12-13\right)=37-39\\ 2\left(-1\right)=-2\\ -2=-2\end{array}$As the left-hand side is equal to right hand side, this signifies that the solution is correct.

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