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Q.3

Expert-verifiedFound in: Page 539

Book edition
Common Core Edition

Author(s)
Ron Larson, Laurie Boswell, Timothy D. Kanold, Lee Stiff

Pages
183 pages

ISBN
9780547587776

**Find the value of x. Then classify the triangle by its angle measures.**

The value of *x *is$x=20\xb0$ and the triangle is **an isosceles triangle**.

One angle of the triangle is$80\xb0$.

Second angle is given as$4x\xb0$.

Third angle is given as$x\xb0$.

**Sum of all angles of a triangle is$180\xb0$.**

The sum of all the angles of a triangle is$180\xb0$.

This gives us,

$4x{}^{\circ}+x{}^{\circ}+80{}^{\circ}=180\xb0$

Add both *x* together.

$5x+80{}^{\circ}=180\xb0$

Subtract 80 from both the sides.

$5x+80{}^{\circ}-80{}^{\circ}=180{}^{\circ}-80\xb0$

This gives us,

$5x=100\xb0$

Now, divide both sides by 5.

$\frac{5x}{5}=\frac{120\xb0}{5}$

This will give us,

$x=20\xb0$

Since, the other two angles of the triangle are 4*x* and *x*.

To find the value of the angles multiply it with 20.

The angle of second side is 4*x*.

Multiply it with 4.

$4x=4\times 20\xb0$

Which gives the value as$80\xb0$.

The angle of the third side is *x*.

And the value of *x* is$x=20\xb0$.

Which gives us the value as$20\xb0$.

The value of *x* is$x=20\xb0$.

One angle is$80\xb0$, Second angle is $80\xb0$ and the third angle is$20\xb0$.

Two sides of the triangle are same and one is different.

Hence, it is an isosceles triangle.

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