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Q. 24

Expert-verifiedFound in: Page 616

Book edition
Common Core Edition

Author(s)
Ron Larson, Laurie Boswell, Timothy D. Kanold, Lee Stiff

Pages
183 pages

ISBN
9780547587776

** Find the slope of the line through the given points.**

**$\left(4,\text{\hspace{0.33em}}2\right),\left(3,\text{\hspace{0.33em}}8\right)$**

The slope of the line through the points $\left(4,2\right),\left(3,8\right)$ is$-6$ .

The given points are $\left(4,2\right),\left(3,8\right)$.

The slope of the line through the points $\left({x}_{1},{y}_{1}\right),\left({x}_{2},{y}_{2}\right)is$$\frac{{y}_{2}-{y}_{1}}{{x}_{2}-{x}_{1}}.$

To find the slope substitute $\left({x}_{1},{y}_{1}\right)=\left(4,2\right)$ and $\left({x}_{2},{y}_{2}\right)=\left(3,8\right)$ into the slope formula then simplify it.

$\begin{array}{c}\frac{{y}_{2}-{y}_{1}}{{x}_{2}-{x}_{1}}=\frac{8-2}{3-4}\\ \frac{{y}_{2}-{y}_{1}}{{x}_{2}-{x}_{1}}=\frac{6}{-1}\\ \frac{{y}_{2}-{y}_{1}}{{x}_{2}-{x}_{1}}=-6\end{array}$

The slope of the line through the points $\left(4,2\right),\left(3,8\right)$ is $-6$ .

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