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Q. 17

Expert-verifiedFound in: Page 624

Book edition
Common Core Edition

Author(s)
Ron Larson, Laurie Boswell, Timothy D. Kanold, Lee Stiff

Pages
183 pages

ISBN
9780547587776

**Find the surface area of the prism, cylinder, or pyramid. Round to the nearest whole number.**

The surface area is **184 square meters**.

The figure is shown below.

$\text{Area of rectangle}=\text{length}\times \text{width}$

$\text{Area of triangle}=\left(\frac{1}{2}\times \text{base}\times \text{height}\right)$

Find the area of the base of the pyramid.

$\begin{array}{c}{\text{Area}}_{\text{1}}=10\times 6\\ =60\end{array}$

The area of the two slant sides of the pyramid.

$\begin{array}{c}{\text{Area}}_{\text{2}}=2\times \left(10\times 5\right)\\ =2\times 50\\ =100\end{array}$

Find the area of the two triangular sides of pyramid.

$\begin{array}{c}{\text{Area}}_{3}=2\times \left(\frac{1}{2}\times 6\times 4\right)\\ =2\times 12\\ =24\end{array}$

Total surface area (*A*) of the figure is equal to the sum of${\text{Area}}_{\text{1}}$ ,${\text{Area}}_{\text{2}}$ and${\text{Area}}_{\text{3}}$ .

$\begin{array}{c}A=100+60+24\\ =184\end{array}$

The surface area of pyramid is 184 square meters.

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