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Let \(\left\\{1, \mathrm{x}, \mathrm{x}^{2}\right\\}\) be a basis for the vector space of polynomials of degree not exceeding 2 . Let $\mathrm{D}, \mathrm{D}^{2}\( and \)\mathrm{D}^{3}$ denote differentiation operators. Find the matrices of \(\mathrm{D}, \mathrm{D}^{2}\) and \(\mathrm{D}^{3}\) relative to the above basis.

Short Answer

Expert verified
The matrices of the differentiation operators D, D^2, and D^3 relative to the given basis are: \[D = \begin{bmatrix}0 & 1 & 0\\0 & 0 & 2\\0 & 0 & 0\end{bmatrix}\] \[D^2 = \begin{bmatrix}0 & 0 & 2\\0 & 0 & 0\\0 & 0 & 0\end{bmatrix}\] \[D^3 = \begin{bmatrix}0 & 0 & 0\\0 & 0 & 0\\0 & 0 & 0\end{bmatrix}\]
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Step 1: Apply Differentiation Operator to Basis Elements

First, we will apply the differentiation operator D to each element of the basis: 1. D(1) = 0 2. D(x) = 1 3. D(x^2) = 2x

Step 2: Express the Resulting Polynomials in Terms of the Basis

Now, we will express the resulting polynomials in terms of the basis elements: 1. 0 = 0 * 1 + 0 * x + 0 * x^2 2. 1 = 1 * 1 + 0 * x + 0 * x^2 3. 2x = 0 * 1 + 2 * x + 0 * x^2

Step 3: Construct the Matrix for Differentiation Operator D

The matrix representation for the differentiation operator D is obtained by placing the coefficients of the basis decomposition in columns. Therefore, the matrix for D is: \[D = \begin{bmatrix}0 & 1 & 0\\0 & 0 & 2\\0 & 0 & 0\end{bmatrix}\]

Step 4: Apply Differentiation Operator D^2 to Basis Elements

Now, we need to apply D^2 (the second derivative) to the basis elements. Since D^2 is the square of the differentiation operator, it is equivalent to applying D twice: 1. D^2(1) = D(D(1)) = D(0) = 0 2. D^2(x) = D(D(x)) = D(1) = 0 3. D^2(x^2) = D(D(x^2)) = D(2x) = 2

Step 5: Express the Resulting Polynomials in Terms of the Basis

We express the resulting polynomials from Step 4 in terms of the basis elements: 1. 0 = 0 * 1 + 0 * x + 0 * x^2 2. 0 = 0 * 1 + 0 * x + 0 * x^2 3. 2 = 2 * 1 + 0 * x + 0 * x^2

Step 6: Construct the Matrix for Differentiation Operator D^2

The matrix representation for the differentiation operator D^2 is obtained by placing the coefficients of the basis decomposition in columns. Therefore, the matrix for D^2 is: \[D^2 = \begin{bmatrix}0 & 0 & 2\\0 & 0 & 0\\0 & 0 & 0\end{bmatrix}\]

Step 7: Apply Differentiation Operator D^3 to Basis Elements

Now, we need to apply D^3 (the third derivative) to the basis elements. Since D^3 is the cube of the differentiation operator, it is equivalent to applying D three times: 1. D^3(1) = D(D^2(1)) = D(0) = 0 2. D^3(x) = D(D^2(x)) = D(0) = 0 3. D^3(x^2) = D(D^2(x^2)) = D(2) = 0

Step 8: Express the Resulting Polynomials in Terms of the Basis

We express the resulting polynomials from Step 7 in terms of the basis elements: 1. 0 = 0 * 1 + 0 * x + 0 * x^2 2. 0 = 0 * 1 + 0 * x + 0 * x^2 3. 0 = 0 * 1 + 0 * x + 0 * x^2

Step 9: Construct the Matrix for Differentiation Operator D^3

The matrix representation for the differentiation operator D^3 is obtained by placing the coefficients of the basis decomposition in columns. Therefore, the matrix for D^3 is: \[D^3 = \begin{bmatrix}0 & 0 & 0\\0 & 0 & 0\\0 & 0 & 0\end{bmatrix}\] So, the matrices of the differentiation operators D, D^2, and D^3 relative to the given basis are: \[D = \begin{bmatrix}0 & 1 & 0\\0 & 0 & 2\\0 & 0 & 0\end{bmatrix}\] \[D^2 = \begin{bmatrix}0 & 0 & 2\\0 & 0 & 0\\0 & 0 & 0\end{bmatrix}\] \[D^3 = \begin{bmatrix}0 & 0 & 0\\0 & 0 & 0\\0 & 0 & 0\end{bmatrix}\]

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Most popular questions from this chapter

Chapter 3

Let \(\mathrm{T}: \mathrm{R}^{2} \rightarrow \mathrm{R}^{2}\) be given by $\mathrm{T}\left(\mathrm{x}_{1}, \mathrm{x}_{2}\right)=\left(4 \mathrm{x}_{1}-2 \mathrm{x}_{2}, 2 \mathrm{x}_{1}+\mathrm{x}_{2}\right)$ and let \(\\{(1,1),(-1,0)\\}\) be a basis for \(\mathrm{R}^{2}\). Compute the matrix of \(\mathrm{T}\) in the given basis.

Chapter 3

Let T: \(\mathrm{R}^{3} \rightarrow \mathrm{R}^{2}\) be given by $\mathrm{T}\left(\mathrm{x}_{1}, \mathrm{x}_{2}, \mathrm{x}_{3}\right)=\left(7 \mathrm{x}_{1}+2 \mathrm{x}_{2}-3 \mathrm{x}_{3}, \mathrm{x}_{2}\right)$ As bases for \(\mathrm{R}^{3}\) and \(\mathrm{R}^{2}\) respectively, let $\mathrm{G}=\left\\{\mathrm{g}_{1}, \mathrm{~g}_{2}, \mathrm{~g}_{3}\right\\}=\\{(1,0,0),(0,1,-1),(0,0,1)\\}$ $\mathrm{H}=\left\\{\mathrm{h}_{1}, \mathrm{~h}_{2}\right\\}=\\{(1,0),(0,-1)\\}$

Chapter 3

Systems of linear transformations and matrices are isomorphic vector spaces. Show by means of an example that the product of two linear transformations can be represented as the product of two matrices with respect to a given basis.

Chapter 3

Let \(\mathrm{S}: \mathrm{R}^{2} \rightarrow \mathrm{R}^{2}\) and $\mathrm{T}: \mathrm{R}^{2} \rightarrow \mathrm{R}^{2}\( be given by \)\mathrm{S}(\mathrm{x}, \mathrm{y})=$ \((x-2 y, 2 x+7 y), T(x, y)=(3 x+2 y, x-y) .\) Find \((S+T)(x, y)\) and \((3 \mathrm{~T})(\mathrm{x}, \mathrm{y})\), in both functional and matrix form.

Chapter 3

Let \(\left\\{\mathrm{e}_{i}\right\\}=\\{(1,0),(0,1)\\}\) and \(\left\\{\mathrm{f}_{i}\right\\}=\\{(1,1),(-1,0)\\}\) be two bases for \(\mathrm{R}^{2}\). Find the transition matrix from \(\left\\{\mathrm{e}_{\mathrm{i}}\right\\}\) to \(\left\\{\mathrm{f}_{\mathrm{i}}\right.\) ).

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