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Give an example of a pair of non-collinear vectors in \(R^{2}\). Then, show that the point \(\left(\mathrm{x}_{1}, \mathrm{x}_{2}\right)=(8,7)\) can be expressed as a linear combination of the non-collinear vectors.

Short Answer

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A pair of non-collinear vectors in \(R^{2}\) could be \( \vec{a} = (1,0) \) and \( \vec{b} = (0,1) \). The point (8,7) can be expressed as a linear combination of these non-collinear vectors by finding scalars 's' and 't' such that \( s\vec{a} + t\vec{b} = (8,7) \). In this case, we have \(s = 8\) and \(t = 7\), so the linear combination is: (8, 7) = 8(1,0) + 7(0,1).
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Step 1: Find a pair of non-collinear vectors in R^2.

Choose arbitrary vectors that are not scalar multiples of each other. One such possible pair could be: \( \vec{a} = (1,0) \) and \( \vec{b} = (0,1) \). Since their directions are different, these two vectors are non-collinear.

Step 2: Express the point (8,7) as a linear combination of the non-collinear vectors

Now we want to find scalars 's' and 't' such that: \( s\vec{a} + t\vec{b} = (8,7) \) Using the vectors defined in step 1, the equation becomes: $$s(1, 0) + t(0, 1) = (8, 7)$$ This simplifies to two separate equations: $$ s = 8 $$ $$ t = 7 $$ Since we found values for 's' and 't' that satisfy the equation, we can express (8,7) as a linear combination of the non-collinear vectors \(\vec{a}\) and \(\vec{b}\): $$ (8, 7) = 8(1,0) +7(0,1) $$

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