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Answers without the blur. Sign up and see all textbooks for free! Q.12.8

Expert-verified Found in: Page 694 ### Introductory Statistics

Book edition OER 2018
Author(s) Barbara Illowsky, Susan Dean
Pages 902 pages
ISBN 9781938168208 # For a given line of best fit, you compute that $r=0.5204$ using $n=9$ data points, and the critical value is 0.666. Can the line be used for prediction? Why or why not?

The critical value associated with degrees of freedom $7$ is $0.666$.Therefore,$r$ is insignificant.

See the step by step solution

## Step 1: Given Information

$r=0.5204$

$n=9$

$criticalvalue=0.666$.

## Step 2: Explanation

The degrees of freedom can be computed as shown below:

$df=n-2$

$=9-2$$=7$

The critical value associated with degrees of freedom $7$ is $0.666$. If $r$ is less than negative critical value or $r$ is greater than positive critical value then $r$ is significant. Here, $r\left(0.5204\right)$ is less than positive critical value $\left(0.666\right)$. Therefore, $r$ is insignificant. ### Want to see more solutions like these? 