Log In Start studying!

Select your language

Suggested languages for you:
Answers without the blur. Sign up and see all textbooks for free! Illustration


Introductory Statistics
Found in: Page 348
Introductory Statistics

Introductory Statistics

Book edition OER 2018
Author(s) Barbara Illowsky, Susan Dean
Pages 902 pages
ISBN 9781938168208

Answers without the blur.

Just sign up for free and you're in.


Short Answer

The data that follow are the square footage (in 1,000 feet squared) of 28 homes.

The sample mean = 2.50 and the sample standard deviation = 0.8302. The distribution can be written as X ~ U(1.5, 4.5).

What is the 90th percentile of square footage for homes?

The value of the 90thpercentile of square footage for homes is 4.2.

See the step by step solution

Step by Step Solution

Step 1: Given information


Sample mean = 2.50

Standard deviation = 0.8302

Step 2: Solution

Here, we need to find the probability density function or height of the X~U(1.5,4.5),

f(x)= height



So, the 90th percentile will be,

P(x<k)= base × height





Recommended explanations on Math Textbooks

94% of StudySmarter users get better grades.

Sign up for free
94% of StudySmarter users get better grades.