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Show that for any two languages \(A\) and \(B\), a language \(J\) exists, where $A \leq \mathrm{T} J\( and \)B \leq \mathrm{T} J$.

Short Answer

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We have shown the existence of a language \(J\) for any two languages \(A\) and \(B\) such that \(A \leq_T J\) and \(B \leq_T J\). We defined \(J = \{0w : w \in A\} \cup \{1x : x \in B\}\) and showed that both \(A\) and \(B\) are Turing reducible to \(J\) by constructing Turing machines that use an oracle for \(J\) to decide if strings are in \(A\) or \(B\).
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Step 1: Define Turing reducibility

Turing reducibility, also known as Turing-Weihrauch reducibility, is a relation between decision problems. Intuitively, a problem \(A\) is Turing reducible to a problem \(B\) (denoted \(A \leq_T B\)), if there exists a Turing machine that can solve problem \(A\) using an oracle for problem \(B\).

Step 2: Define languages A and B

Let \(A\) and \(B\) be two arbitrary languages. We want to define a new language \(J\) such that both \(A\) and \(B\) can be Turing reduced to \(J\).

Step 3: Define language J

Let's define \(J\) as the following: \[ J = \{0w : w \in A\} \cup \{1x : x \in B\} \] Language \(J\) is a combination of the languages \(A\) and \(B\) with an added "tag" at the beginning of the strings. For strings in \(A\), a \(0\) is added to the beginning, and for strings in \(B\), a \(1\) is added to the beginning. This allows us to differentiate between strings from \(A\) and strings from \(B\).

Step 4: Show A is Turing reducible to J

If we have an oracle for \(J\), we can decide if any given string \(w\) is in \(A\) by adding a \(0\) to the beginning of \(w\) and querying the oracle for \(0w\). If the oracle returns that \(0w \in J\), then we know \(w \in A\), otherwise \(w \notin A\). So, we can create a Turing machine that solves \(A\) using an oracle for \(J\), which by definition means \(A \leq_T J\).

Step 5: Show B is Turing reducible to J

Similarly, we can also decide if a given string \(x\) is in \(B\) by adding a \(1\) to the beginning of \(x\) and querying the oracle for \(1x\). If the oracle returns that \(1x \in J\), then we know \(x \in B\), otherwise \(x \notin B\). This implies that we can create a Turing machine that solves \(B\) using an oracle for \(J\), which by definition means \(B \leq_T J\).

Step 6: Conclusion

In this exercise, we have proven the existence of a language \(J\) such that for any two languages \(A\) and \(B\), both \(A\) and \(B\) are Turing reducible to \(J\).

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