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Convert the following regular expressions to NFAs using the procedure given in Theorem 1.54. In all parts, \(\Sigma=\\{\mathrm{a}, \mathrm{b}\\}\). a. \(\mathrm{a}(\mathrm{abb})^{*} \cup \mathrm{b}\) b. \(a^{+} \cup(a b)^{+}\) c. \(\left(\mathrm{a} \cup \mathrm{b}^{+}\right) \mathrm{a}^{+} \mathrm{b}^{+}\)

Short Answer

Expert verified
a. The NFA for \( \mathrm{a}(\mathrm{abb})^{*} \cup \mathrm{b} \) is obtained by creating separate NFAs for \( \mathrm{a} \), \( \mathrm{abb} \), and \( \mathrm{b} \), applying closure, concatenation, and union operations, then simplifying the result. b. The NFA for \( a^{+} \cup(a b)^{+} \) is constructed by creating separate NFAs for \( a \) and \( a b \), applying the plus and union operations, and simplifying the result. c. The NFA for \( \left(\mathrm{a} \cup \mathrm{b}^{+}\right) \mathrm{a}^{+} \mathrm{b}^{+} \) is derived by creating separate NFAs for \( a \), \( b^{+} \), \( a^{+} \), and \( b^{+} \), applying union and concatenation operations, and simplifying the final NFA.
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Step 1: a. Convert \( \mathrm{a}(\mathrm{abb})^{*} ∪ \mathrm{b} \) to NFA

1. Create separate NFAs for \( \mathrm{a} \), \( \mathrm{abb} \), and \( \mathrm{b} \). 2. Use the closure operation to create an NFA for \( (\mathrm{abb})^{*} \). 3. Concatenate the NFAs for \( \mathrm{a} \) and \( (\mathrm{abb})^{*} \). 4. Apply the union operation to combine the NFAs for \( \mathrm{a}(\mathrm{abb})^{*} \) and \( \mathrm{b} \). 5. Simplify the resulting NFA, if possible.

Step 2: b. Convert \( a^{+} \cup(a b)^{+} \) to NFA

1. Create separate NFAs for \( a \) and \( a b \). 2. Use the plus operation to create NFAs for \( a^{+} \) and \( (a b)^{+} \). 3. Apply the union operation to combine the NFAs for \( a^{+} \) and \( (a b)^{+} \). 4. Simplify the resulting NFA, if possible.

Step 3: c. Convert \( \left(\mathrm{a} \cup \mathrm{b}^{+}\right) \mathrm{a}^{+} \mathrm{b}^{+} \) to NFA

1. Create separate NFAs for \(a\), \( b^{+} \), \( a^{+} \), and \( b^{+} \). 2. Apply the union operation to combine the NFAs for \( a \) and \( b^{+} \) and create an NFA for \( \left(\mathrm{a} \cup \mathrm{b}^{+}\right) \). 3. Concatenate the NFAs for \( \left(\mathrm{a} \cup \mathrm{b}^{+}\right) \), \( a^{+} \), and \( b^{+} \). 4. Simplify the resulting NFA, if possible.

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Most popular questions from this chapter

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