Book edition OER 2017

Author(s) OPENSTAX

Pages 1346 pages

ISBN 9780998625720

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Short Answer

In the following exercises, find the sum of the first 30 terms of each arithmetic sequence.
12, 18, 24, 30, 36, …

The obtained sum is 2970.

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Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1. Given Information.

The arithmetic sequence is $12, 18, 24, 30, 36, \dots$ .

Step 2. Find the common difference d.

Find the common difference of consecutive terms.

$\begin{array}{rcl} d & = & 18 - 12 \\ = & 6 \end{array}$

And, now find the 30th term of the sequence.

$\begin{array}{rcl} a_{30} & = & 12 + (30 - 1) 6 \\ = & 12 + 174 \\ = & 186 \end{array}$

Step 3. Use the sum formula.

Use the sum formula $S_{n} = \frac{n}{2} (a_{1} + a_{n})$ to find the sum of the thirtieth term.

$\begin{array}{rcl} S_{30} & = & \frac{30}{2} (12 + 186) \\ = & 15 (198) \\ = & 2970 \end{array}$

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Intermediate Algebra

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Short Answer

In the following exercises, find the sum of the first 30 terms of each arithmetic sequence.
12, 18, 24, 30, 36, …

Step by Step Solution

Step 1. Given Information.

Step 2. Find the common difference d.

Step 3. Use the sum formula.

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Intermediate Algebra

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In the following exercises, find the sum of the first 30 terms of each arithmetic sequence. 12, 18, 24, 30, 36, …

Step by Step Solution

Step 1. Given Information.

Step 2. Find the common difference d.

Step 3. Use the sum formula.

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In the following exercises, find the sum of the first 30 terms of each arithmetic sequence.
12, 18, 24, 30, 36, …