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Q4.

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Geometry
Found in: Page 583
Geometry

Geometry

Book edition Student Edition
Author(s) Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen
Pages 227 pages
ISBN 9780395977279

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Short Answer

Prove that you can see all of yourself in a mirror that is only half as tall as you are. (Hint: Study the diagram on page 582.)

It is proved that you can see all of yourself in a mirror that is only half as tall as you are.

See the step by step solution

Step by Step Solution

Step 1. Given Information.

The given statement is you can see all of yourself in a mirror that is only half as tall as you are.

Step 2. Proof.

Consider you are standing in front of a mirror of height FH and your height is AE.

Point C represents your eye, A represents top of your head, E represents foot, B is the mid-point between your eye and top of your head, D is the mid-point between your eye and foot, F is the bottom of the mirror, H is the top of the mirror and G is a point in the mirror parallel to your eyes.

Since,

AE=AB+BC+CD+DEAE=BC+BC+CD+CD AB=BC,CD=DEAE=2BC+CD iandHF=HG+GF ii

In similar triangles CGF and CDF

CF is common sideCD=DFtherefore,CD=GF

In similar triangles BCH and CGH

CH is common sideBH=CGtherefore, BC=HG

Substitute the values of HG and GF in equation i.

HF=HG+GF iiHF=BC+CD CD=GF,BC=HGHF=AE2 AE=2BC+CD

Step 3. Conclusion.

It is proved that you can see all of yourself in a mirror that is only half as tall as you are.

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