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Q23.

Expert-verifiedFound in: Page 288

Book edition
Student Edition

Author(s)
Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen

Pages
227 pages

ISBN
9780395977279

**Refer to the figure at the right.**

**If $LM=6$and $JM=4$ find $MK$.**

The required value** **is $MK=6$.

In the given figure,

$LM=6\u200a\u200a\&\u200a\u200aJM=4$

When the altitude is drawn to the hypotenuse of a right triangle,

The length of the altitude is the geometric mean between the segments of the hypotenuse.

In the given triangle,

$\begin{array}{c}\frac{JM}{LM}=\frac{LM}{MK}\\ \frac{4}{6}=\frac{4}{MK}\\ MK=6\end{array}$

Therefore, the required value is**$MK=6$**.

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