Find something interesting to prove. Then prove it. Answers may vary.
It is proved that .
The opposite sides of a parallelogram are congruent.
In , and are opposite sides. Therefore, .
From the given figure, it can be observed that and is a transversal then and are alternate interior angles such that, .
As , and then by ASA postulate, .
As , then by corresponding parts of congruent triangles, .
Hence it is proved that .
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