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Q29

Expert-verified
Geometry
Found in: Page 170
Geometry

Geometry

Book edition Student Edition
Author(s) Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen
Pages 227 pages
ISBN 9780395977279

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Illustration

Short Answer

Given:PQRS; localid="1637659881844" PJ¯RK¯

Prove: localid="1637659923835" SJ¯QK¯

It is proved that SJ¯QK¯.

See the step by step solution

Step by Step Solution

Step 1. Apply property of parallelogram.

The opposite sides of a parallelogram are congruent.

From the given figure, it can be observed that SP¯ and RQ¯ are opposite sides of a PQRS.

Therefore, SP¯RQ¯

Step 2. Apply property of parallelogram.

The opposite angles of a parallelogram are congruent.

From the given figure, it can be observed that P and R are opposite angles of a PQRS.

Therefore, PR.

Step 3. Apply SAS postulate.

If two sides and the included angle of one triangle are congruent to two sides and included angle of another triangle, then the triangles are congruent.

Here, PJ¯RK¯, PR and SP¯RQ¯, then by SAS postulate ΔSPJΔKRQ.

Step 4. Description of step.

As ΔSPJΔKRQ, then by corresponding parts of congruent triangles, SJ¯QK¯.

Hence it is proved that SJ¯QK¯.

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