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Q25

Expert-verified
Geometry
Found in: Page 176
Geometry

Geometry

Book edition Student Edition
Author(s) Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen
Pages 227 pages
ISBN 9780395977279

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Short Answer

Write a paragraph proof.

Given: ABCD;  BEDF

Prove: AECF is a .

(Hint: A short proof is possible if certain auxiliary segments ate drawn.)

Two pairs of opposite sides AEFC and AFCE in AECF are parallel therefore, AECF is a parallelogram.

See the step by step solution

Step by Step Solution

Step 1. Relation between triangle DAE and triangle BCF

In triangles ΔDAE and ΔBCF.

ADBC    (ABCD is a rhombus)

ADCABC (ABCD is a rhombus)

ADECBF   ( EDC & ABF are the equal angle of parallelogram made of parallel sides two parallelograms)

ABCD is a parallelogram.

Similarly, ADCABC ( ABCD is a rhombus),

EDC & ABF are equal angles of parallelogram made of parallel sides.

ADECBF

DEBF BEDF is a parallelogram.

Therefore, by SAS postulate ΔDAEΔBCF.

By CPCT, AEFC.

Step 2. Relation between triangle AFB and triangle CDE

In triangles ΔAFB & ΔCDE.

DEBFBEDF is a parallelogram

Since, EDC & ABF are equal angles of parallelogram made of parallel sides.

ADECBF  

DCBABEDF is a parallleogram

Therefore, by SAS postulate ΔAFBΔCED.

By CPCT, AFCE.

Step 3. State the conclusion

Since two pairs of opposite sides AEFC and AFCE in AECF are parallel, therefore, AECF is a parallelogram.

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