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Q. 17

Expert-verifiedFound in: Page 526

Book edition
Student Edition

Author(s)
Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen

Pages
227 pages

ISBN
9780395977279

**Find the center and radius of each circle.**

**${\left(x+3\right)}^{2}+{y}^{2}=49$**

The center is (-3, 0) and the radius is 7.

The given equation is ${\left(x+3\right)}^{2}+{y}^{2}=49$.

We have to find the center and the radius of the given circle.

We compare the given equation${\left(x+3\right)}^{2}+{y}^{2}=49$ with the standard form of a circle:${\left(x-a\right)}^{2}+{\left(y-b\right)}^{2}={r}^{2}$.

Here *(a, b)* is the center and *r* being the radius.

Comparing the two equations we get: *a = - 3, b = 0 *and* r = 7*.

So, the center is (-3, 0) and the radius is 7.

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