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Q. 17

Expert-verified

Geometry

Found in: Page 526

Book edition Student Edition

Author(s) Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen

Pages 227 pages

ISBN 9780395977279

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Short Answer

Find the center and radius of each circle.
${(x + 3)}^{2} + y^{2} = 49$

The center is (-3, 0) and the radius is 7.

See the step by step solution

Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step-1 – Given

The given equation is ${(x + 3)}^{2} + y^{2} = 49$ .

Step-2 – To determine

We have to find the center and the radius of the given circle.

Step-3 – Calculation

We compare the given equation ${(x + 3)}^{2} + y^{2} = 49$ with the standard form of a circle: ${(x - a)}^{2} + {(y - b)}^{2} = r^{2}$ .

Here (a, b) is the center and r being the radius.

Comparing the two equations we get: a = - 3, b = 0 and r = 7.

So, the center is (-3, 0) and the radius is 7.

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