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Found in: Page 120


Book edition Student Edition
Author(s) Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen
Pages 227 pages
ISBN 9780395977279

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Short Answer

Plot the given points on graph paper. Draw ΔABC and DE¯. Find two locations of point F such that ΔABCΔDEF.

A1,0 B5,4 C6,1 D1,0 E5,4.

Two points of F such that ΔABCΔDEFare 2,5 and 6,1.

See the step by step solution

Step by Step Solution

Step 1. Plot the diagram.

Plot A1,0, B5,4, C6,1 D1,0, E5,4 and DE¯ on the graph paper as shown below:

Step 2. Show the calculation.

The two triangles are said to be congruent if they are copies of each other and if their vertices are superposed, then can say that the corresponding angles and the sides of the triangles are congruent.

Now, to locate point F so that ΔABCΔDEF, and location of point F can be rather on right side or on left side of DE¯.

If ΔABCΔDEF then, corresponding parts of congruent triangles are congruent.



In the above graph, to reach point C from point A, move 5 boxes to the left and then, 1 box vertically above. In the same manner, to reach point F from point D, move 5 boxes vertically above and then, 1 box to the right. If from point D, will move 5 boxes to the right and then, 1 box vertically above, will get another location of point F.

See the graph given below:

Thus, from the graph conclude that point F can be 2,5 and 6,1 such that ΔABCΔDEF.

Step 3 - State the conclusion.

Therefore, point F can be 2,5 and 6,1 such that ΔABCΔDEF.

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