Log In Start studying!

Select your language

Suggested languages for you:

Americas

English (US)

Europe

Q3.

Expert-verified

Geometry

Found in: Page 332

Book edition Student Edition

Author(s) Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen

Pages 227 pages

ISBN 9780395977279

Answers without the blur.

Just sign up for free and you're in.

Register for Free I’ll do it later

Short Answer

Find the number of odd and even vertices in each network. Imagine travelling each network to see if it can be traced without backtracking.

The number of odd and even vertices is $2$ and $6 .$

See the step by step solution

Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1. Given information:

The given figure is as follows:

Step 2. Concept use.

A vertex with odd number of edges attached to it is called odd vertex and a vertex with even number of edges attached to it is called even vertex.

Step 3. Applying the concept.

In the given network, by observing, the total number of vertices $= 8 .$

A vertex with odd number of edges attached to it is called odd vertex and a vertex with even number of edges attached to it is called even vertex.

Hence, the number of odd vertices $= 2 .$

The number of even vertices $= 6 .$

Most popular questions for Math Textbooks

For each exercise draw $⊙ O$ with radius $12$ . Then draw radii $\bar{O A}$ and to $\bar{O B}$ form an angle with the measure named. Find the length of $\bar{A B}$ .

b. $m ∠ A O B = 180 °$

$\bar{J T}$ is tangent to $⊙$ $O$ at $T$ . Complete.

If $m ∠ T O J = 60$ and $O T = 6$ , then $J O = ?$

Given $\bar{P A}$ and $\bar{P B}$ are tangents to $⊙ o .$

Use the diagram at the right to explain how the corollary on page $333$

follows from Theorem $9 - 1 .$

Find the measure of central $∠ 1 .$

Find the number of odd and even vertices in each network. Imagine travelling each network to see if it can be traced without backtracking.

Want to see more solutions like these?

Sign up for free to discover our expert answers

Get Started - It’s free

Recommended explanations on Math Textbooks

94% of StudySmarter users get better grades.

Sign up for free