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Problem 493

What is the measure of the interior angle of a regular triangle? A regular quadrilateral? A regular 10 -gon? A regular 2000 -gon?

Short Answer

Expert verified
The interior angle measures of the given regular polygons are as follows: Regular triangle (3 sides) - \(60°\); Regular quadrilateral (4 sides) - \(90°\); Regular 10-gon (10 sides) - \(144°\); Regular 2000-gon (2000 sides) - approximately \(179.64°\).
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Step 1: Regular Triangle (n=3)

To find the interior angle measure of a regular triangle, we will use the formula: \(Interior \ angle \ measure = \frac{(n-2) × 180°}{n}\) \(= \frac{(3-2) × 180°}{3}\) \(= \frac{1 × 180°}{3}\) \(= 60°\) So, the measure of the interior angle of a regular triangle is 60°.

Step 2: Regular Quadrilateral (n=4)

To find the interior angle measure of a regular quadrilateral, we will use the formula: \(Interior \ angle \ measure = \frac{(n-2) × 180°}{n}\) \(= \frac{(4-2) × 180°}{4}\) \(= \frac{2 × 180°}{4}\) \(= 90°\) So, the measure of the interior angle of a regular quadrilateral is 90°.

Step 3: Regular 10-gon (n=10)

To find the interior angle measure of a regular 10-gon, we will use the formula: \(Interior \ angle \ measure = \frac{(n-2) × 180°}{n}\) \(= \frac{(10-2) × 180°}{10}\) \(= \frac{8 × 180°}{10}\) \(= 144°\) So, the measure of the interior angle of a regular 10-gon is 144°.

Step 4: Regular 2000-gon (n=2000)

To find the interior angle measure of a regular 2000-gon, we will use the formula: \(Interior \ angle \ measure = \frac{(n-2) × 180°}{n}\) \(= \frac{(2000-2) × 180°}{2000}\) \(= \frac{1998 × 180°}{2000}\) \(= 179.64°\) So, the measure of the interior angle of a regular 2000-gon is approximately 179.64°.

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