Suggested languages for you:

Americas

Europe

Problem 442

# Find the area of a square whose perimeter is $$20 \mathrm{ft}$$.

Expert verified
The area of a square with a perimeter of $$20 \mathrm{ft}$$ is $$25 \mathrm{ft}^2$$.
See the step by step solution

## Step 1: Determine the side length of the square

Since the perimeter of a square is given by the formula $$P = 4s$$, where $$P$$ is the perimeter and $$s$$ is the side length, we can find the side length by dividing the perimeter by 4: $s = \frac{P}{4}$ Given the perimeter $$P = 20 \mathrm{ft}$$, we can plug in the value and find the side length: $s = \frac{20 \mathrm{ft}}{4}$ $s = 5 \mathrm{ft}$ Now we know the side length of the square is $$5 \mathrm{ft}$$.

## Step 2: Calculate the area of the square

To find the area of a square, we can use the formula $$A = s^2$$, where $$A$$ is the area and $$s$$ is the side length. We know that the side length of the square is $$5 \mathrm{ft}$$, so we can plug in the value to find the area: $A = (5 \mathrm{ft})^2$ $A = 25 \mathrm{ft}^2$ Hence, the area of the square is $$25 \mathrm{ft}^2$$.

We value your feedback to improve our textbook solutions.

## Access millions of textbook solutions in one place

• Access over 3 million high quality textbook solutions
• Access our popular flashcard, quiz, mock-exam and notes features

## Join over 22 million students in learning with our Vaia App

The first learning app that truly has everything you need to ace your exams in one place.

• Flashcards & Quizzes
• AI Study Assistant
• Smart Note-Taking
• Mock-Exams
• Study Planner