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Q-37E

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Fundamentals Of Differential Equations And Boundary Value Problems
Found in: Page 435
Fundamentals Of Differential Equations And Boundary Value Problems

Fundamentals Of Differential Equations And Boundary Value Problems

Book edition 9th
Author(s) R. Kent Nagle, Edward B. Saff, Arthur David Snider
Pages 616 pages
ISBN 9780321977069

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Short Answer

Question: Let

Show that fn(0)=0 for n=0,1,2.... and hence that the Maclaurin series for f(x) is 0+0+0+.... , which converges for all x but is equal to f(x) only when x=0 . This is an example of a function possessing derivatives of all orders (at x0 =0 ), whose Taylor series converges, but the Taylor series (about x0 =0) does not converge to the original function! Consequently, this function is not analytic at x=0.

Function is not analytic at x=0 .

See the step by step solution

Step by Step Solution

Step 1: Taylor series

For a function f(x) the Taylor series expansion about a point x0 is given by, f(x-x0)=f(x0)+f'(x0).(x-x0)+f"(x0).(x-x0)22!+ f "' (x0).(x-x0)33!+....

Step 2: The derivatives of f

Let x0 , then f(x)=e -1x2 .

For , the derivatives of f are:

f'(x)=e

f''(x)=e 2x6-6x4

f'''(x)=e -12x7+24x5+4x9-6x4

Note that f(n)(x) will be of the form e p(x), where p(x) is some polynomial.

From the definition of f it follows that, f(0)=0 .

Step 3: To calculate the derivative at x=0

We need to calculate the derivative at x=0 by definition,

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