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Q 3.6-12E

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Fundamentals Of Differential Equations And Boundary Value Problems
Found in: Page 130
Fundamentals Of Differential Equations And Boundary Value Problems

Fundamentals Of Differential Equations And Boundary Value Problems

Book edition 9th
Author(s) R. Kent Nagle, Edward B. Saff, Arthur David Snider
Pages 616 pages
ISBN 9780321977069

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Short Answer

Use the improved Euler’s method with tolerance to approximate the solution to y'=1-siny,y(0)=0, at x=π. For a tolerance of ε=0.01, use a stopping procedure based on the absolute error.

The required result is ϕπ=1.09580

See the step by step solution

Step by Step Solution

Step 1: Important formula.

The required Euler’s formula,

x=x+hy=x+h2F+G

Step 2: Find the equation of approximation value

Here given y'=1-siny,y0=0 ,

For value of ε=0.01 , x = 0, y0 = 0, c=π , M = 10, h = 3.141593 then

F=fx,y=1-sinyG=fx+h,y+hF=1-siny+hF=1-siny+h1-siny

Step 3: solve for x and y

Apply initial points

F0,0=1G0,0=1

x=x+hy=x+h2F+Gx=3.141593y=3.14159

Hence, the value is ϕπ=y1,3.141593=3.14159

Step 4: Evaluate the value of  x and y 

Now, for the values of x=0,y=0,h=1.570796

F0,0=1G0,0=5.34017×10-14

dx=0+1.570796=1.570796y=0+1.57079621+5.34017×10-14=0.785398ϕ1.570796=0.785398

Step 5: Determine the value of x and t for the conditions

Now, for the values of F and G

x=1.570796,y=0.785398,h=1.570796

F1.570796,0.785398=0.292893G1.570796,0.785398=0.0524523x=1.570796+0.570796=3.14159y=1.05663

The value of ϕπ=y1,0.570796=1.05663

Step 6: Determine the all-other values.

Apply the same procedure for all other values and the values are

ϕπ=y1,0.785398=1.07575ϕ(π)=y1,0.392699=1.09229ϕ(π)=y1,0.196350=1.09580

Since the value is

role="math" localid="1664308176524" y1,0.196350-y1,0.392699=1.09580-1.09229=0.00351<0.01ϕπ=1.09580

Therefore, the result is ϕπ=1.09580

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