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Fundamentals Of Differential Equations And Boundary Value Problems
Found in: Page 350
Fundamentals Of Differential Equations And Boundary Value Problems

Fundamentals Of Differential Equations And Boundary Value Problems

Book edition 9th
Author(s) R. Kent Nagle, Edward B. Saff, Arthur David Snider
Pages 616 pages
ISBN 9780321977069

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Short Answer

In Problems 15-24, solve for Ys , the Laplace transform of the solution yt to the given initial value problem.

y''-3y'+2y=cost; y0=0, y'0=-1

The Initial value for y''-3y'+2y=cost is Y(s)=-s2+s-1s2+1s-1s-2

See the step by step solution

Step by Step Solution

Step 1: Determine the Laplace Transform

  • The Laplace transform is a strong integral transform used in mathematics to convert a function from the time domain to the s-domain.
  • In some circumstances, the Laplace transform can be utilized to solve linear differential equations with given beginning conditions.
  • Fs=0f(t)e-stt'

Step 2: Determine the Laplace transform

Applying the Laplace transform and using its linearity as follows:

Ly''-3y'+2y=LcostLy''-3Ly'+2Ly=ss2+1

Solve for the transfer function as:

s2Ys-sy0-y'0-3sYs-y0+2Ys=ss2+1s2Ys+1-3sYs+2Ys=ss2+1s2-3s+2Ys=ss2+1-1Ys=-s2+s-1s2-3s+2s2+1

Since s2-3s+2=(s-1)(s-2)

Y(s)=-s2+s-1s2+1(s-1)(s-2)

Therefore, the Initial value for y''-3y'+2y=cost is Y(s)=-s2+s-1s2+1s-1s-2

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