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Q27 E

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Fundamentals Of Differential Equations And Boundary Value Problems
Found in: Page 14
Fundamentals Of Differential Equations And Boundary Value Problems

Fundamentals Of Differential Equations And Boundary Value Problems

Book edition 9th
Author(s) R. Kent Nagle, Edward B. Saff, Arthur David Snider
Pages 616 pages
ISBN 9780321977069

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Short Answer

In Problems 23-28, determine whether Theorem 1 implies that the given initial value problem has a unique solution.

ydydx=x, y(1)=0

The hypotheses of Theorem 1 are not satisfied.

The initial value problem does not have a unique solution.

See the step by step solution

Step by Step Solution

Step 1: Finding the partial derivative of the given relation concerning y

Here, fx,y=xy and fy=-xy2

Step 2: Determining whether Theorem 1 implies the existence of a unique solution or not

From Step 1, we find that fy is not continuous or even defined when y=0. Consequently, there is no rectangle containing the point 1,0, in which both fx,y and fy are continuous. Because the hypotheses of Theorem 1 do not hold, we cannot use Theorem 1 to determine whether the given initial value problem does or does not have a unique solution. It turns out that this initial value problem has more than one solution.

Hence, Theorem 1 implies that the given initial value problem does not have a unique solution.

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